Sort Stacked Series in Grouped Charts
Environment
| Product | Progress® Kendo UI® Chart for jQuery |
| Operating System | Windows 10 64bit |
| Visual Studio Version | Visual Studio 2017 |
| Preferred Language | JavaScript |
Description
How can I set the order of the stacked series in a grouped Chart?
Solution
The order of the stacked series in a grouped chart cannot be set through the sort option of the data source.
The reason for this behavior is that the grouping overrides the sort order as part of its implementation. In effect, the sort order is respected only within the resulting groups. Still, you can influence the final order of the stacked series as follows:
- Collect the stack values in an array. The stackValue can be obtained from the labels.template.
- Sort the categories based on the stack values array.
The following example demonstrates how to sort stacked series values in a grouped Kendo UI Chart.
<div id="chart"></div>
<script>
var _globalTimeOut,
redrawChart = true,
myValues = {};
var data = [{
daysOut: 1,
type: "A",
requestor: "Adam"
},{
daysOut: 2,
type: "A",
requestor: "Bonnie"
},{
daysOut: 7,
type: "A",
requestor: "Connor"
},{
daysOut: 4,
type: "B",
requestor: "Adam"
},{
daysOut: 6,
type: "B",
requestor: "Bonnie"
},{
daysOut: 4,
type: "B",
requestor: "Zach"
},{
daysOut: 3,
type: "B",
requestor: "Amber"
}];
$("#chart").kendoChart({
"dataSource": {
data: data,
group: {
field: "type"
}
},
series: [{
field: "daysOut",
type: "bar",
categoryField: "requestor",
labels: {background: "", visible: true, template: "# if(stackValue) { stackValues[category] = stackValue; } #"},
stack: true
}],
dataBound: function() {
// Sort on data change
needsSort = true;
stackValues = {};
},
legendItemClick: function() {
// Sort on series toggle
needsSort = true;
},
render: function(e) {
triggerSorting(e);
}
});
function triggerSorting(e) {
if (!needsSort) {
return;
}
needsSort = false;
var axis = e.sender.options.categoryAxis;
axis.categories = axis.categories.sort(function (a, b) {
if (stackValues[a] < stackValues[b]) {
return -1;
}
if (stackValues[a] > stackValues[b]) {
return 1;
}
return 0;
});
e.sender.redraw();
}
</script>